How many tons of ammonium nitrate (34-0-0) are needed to deliver 300 pounds of N per acre to 40 acres?

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To determine how many tons of ammonium nitrate (34-0-0) are needed to deliver 300 pounds of nitrogen (N) per acre for 40 acres, we first calculate the total amount of nitrogen required.

You multiply the amount of nitrogen needed per acre (300 pounds) by the number of acres (40):

300 pounds/acre × 40 acres = 12,000 pounds of N needed in total.

Since ammonium nitrate is 34% nitrogen, we can calculate the amount of ammonium nitrate needed to supply this amount of nitrogen. This is done using the following formula:

Total pounds of ammonium nitrate needed = Total pounds of nitrogen needed / Percentage of nitrogen in the ammonium nitrate.

Thus, we divide the total pounds of nitrogen (12,000 pounds) by the nitrogen percentage (0.34 or 34%):

12,000 pounds / 0.34 = approximately 35,294 pounds of ammonium nitrate needed.

Next, to convert pounds into tons, we recognize that there are 2,000 pounds in a ton:

35,294 pounds / 2,000 = approximately 17.6 tons of ammonium nitrate required.

Therefore, the answer of 17.6 tons accurately

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